A particle of mass m begins to slide down a fixed smooth sphere from the top. What is its tangential acceleration when it breaks off the sphere ?
A
B
C
g
D
Text Solution
Verified by ExpertsThe correct answer is:
B
at loose contact N = 0
mg cos θ = 
....(i)
from energy conservation
mgR(1 – cos θ) = 
mv2 ....(ii)
from (i) & (ii)
cos θ = 
⇒ sin θ = 
tangential acceleration = g sin θ = 
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